A ball is thrown upwards with a speed of 20 m/s. How long will it take to reach the maximum height? (Take g = 10 m/s²) (2023)

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Q: A ball is thrown upwards with a speed of 20 m/s. How long will it take to reach the maximum height? (Take g = 10 m/s²) (2023)

Solution: Time to reach maximum height = initial velocity / g = 20 / 10 = 2 s.

Steps: 7

Step 1: Understand that when a ball is thrown upwards, it will eventually stop rising and reach a maximum height before falling back down.
Step 2: Know that the initial speed of the ball is 20 m/s.
Step 3: Recognize that gravity (g) pulls the ball down at a rate of 10 m/s².
Step 4: To find out how long it takes to reach the maximum height, use the formula: Time = Initial Velocity / g.
Step 5: Plug in the values: Time = 20 m/s / 10 m/s².
Step 6: Calculate the time: 20 divided by 10 equals 2 seconds.
Step 7: Conclude that it takes 2 seconds for the ball to reach its maximum height.