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A ball is thrown vertically upwards with a speed of 15 m/s. How high will it ris
A ball is thrown vertically upwards with a speed of 15 m/s. How high will it rise before coming to a stop? (2023)
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Practice Questions
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Q1
A ball is thrown vertically upwards with a speed of 15 m/s. How high will it rise before coming to a stop? (2023)
11.25 m
15 m
22.5 m
30 m
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Using the formula: height = (initial velocity^2) / (2 * g), where g = 9.8 m/s². Height = (15^2) / (2 * 9.8) = 11.25 m.
Questions & Step-by-step Solutions
1 item
Q
Q: A ball is thrown vertically upwards with a speed of 15 m/s. How high will it rise before coming to a stop? (2023)
Solution:
Using the formula: height = (initial velocity^2) / (2 * g), where g = 9.8 m/s². Height = (15^2) / (2 * 9.8) = 11.25 m.
Steps: 8
Show Steps
Step 1: Identify the initial speed of the ball, which is 15 m/s.
Step 2: Identify the acceleration due to gravity, which is approximately 9.8 m/s².
Step 3: Use the formula for height: height = (initial velocity^2) / (2 * g).
Step 4: Substitute the initial velocity (15 m/s) into the formula: height = (15^2) / (2 * 9.8).
Step 5: Calculate 15^2, which is 225.
Step 6: Calculate 2 * 9.8, which is 19.6.
Step 7: Divide 225 by 19.6 to find the height: height = 225 / 19.6.
Step 8: Perform the division to get the height, which is approximately 11.25 m.
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