A ball is thrown vertically upwards with a speed of 15 m/s. How high will it ris

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Question: A ball is thrown vertically upwards with a speed of 15 m/s. How high will it rise before coming to a stop? (2023)

Options:

Correct Answer: 11.25 m

Solution:

Using the formula: height = (initial velocity^2) / (2 * g), where g = 9.8 m/s². Height = (15^2) / (2 * 9.8) = 11.25 m.

A ball is thrown vertically upwards with a speed of 15 m/s. How high will it rise before coming to a stop? (2023)

A ball is thrown vertically upwards with a speed of 15 m/s. How high will it rise before coming to a stop? (2023)

Correct Answer: 11.25 m

Step 1: Identify the initial speed of the ball, which is 15 m/s.
Step 2: Identify the acceleration due to gravity, which is approximately 9.8 m/s².
Step 3: Use the formula for height: height = (initial velocity^2) / (2 * g).
Step 4: Substitute the initial velocity (15 m/s) into the formula: height = (15^2) / (2 * 9.8).
Step 5: Calculate 15^2, which is 225.
Step 6: Calculate 2 * 9.8, which is 19.6.
Step 7: Divide 225 by 19.6 to find the height: height = 225 / 19.6.
Step 8: Perform the division to get the height, which is approximately 11.25 m.

Kinematics – The study of motion, specifically how objects move under the influence of forces, including the equations of motion for objects in free fall.
Energy Conservation – Understanding that the kinetic energy of the ball is converted into potential energy at the highest point of its trajectory.