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In a circuit with a 24V battery and two 8Ω resistors in series, what is the tota
In a circuit with a 24V battery and two 8Ω resistors in series, what is the total current? (2022)
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In a circuit with a 24V battery and two 8Ω resistors in series, what is the total current? (2022)
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Total resistance R = 8Ω + 8Ω = 16Ω. Current I = V/R = 24V / 16Ω = 1.5A.
Questions & Step-by-step Solutions
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Q
Q: In a circuit with a 24V battery and two 8Ω resistors in series, what is the total current? (2022)
Solution:
Total resistance R = 8Ω + 8Ω = 16Ω. Current I = V/R = 24V / 16Ω = 1.5A.
Steps: 6
Show Steps
Step 1: Identify the voltage of the battery, which is 24V.
Step 2: Identify the resistance of each resistor, which is 8Ω.
Step 3: Since the resistors are in series, add their resistances together: 8Ω + 8Ω = 16Ω.
Step 4: Use Ohm's Law to find the current. Ohm's Law states that Current (I) = Voltage (V) / Resistance (R).
Step 5: Substitute the values into the formula: I = 24V / 16Ω.
Step 6: Calculate the current: 24V divided by 16Ω equals 1.5A.
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