In a parallel circuit with two resistors of 6Ω and 3Ω, what is the total resista

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Question: In a parallel circuit with two resistors of 6Ω and 3Ω, what is the total resistance? (2019)

Options:

Correct Answer: 4Ω

Solution:

Using the formula 1/R_eq = 1/R1 + 1/R2, we get 1/R_eq = 1/6 + 1/3 = 1/6 + 2/6 = 3/6, thus R_eq = 2Ω.

In a parallel circuit with two resistors of 6Ω and 3Ω, what is the total resistance? (2019)

In a parallel circuit with two resistors of 6Ω and 3Ω, what is the total resistance? (2019)

Step 1: Identify the resistors in the parallel circuit. We have R1 = 6Ω and R2 = 3Ω.
Step 2: Write down the formula for total resistance in a parallel circuit: 1/R_eq = 1/R1 + 1/R2.
Step 3: Substitute the values of R1 and R2 into the formula: 1/R_eq = 1/6 + 1/3.
Step 4: Convert 1/3 to have a common denominator with 1/6. 1/3 = 2/6.
Step 5: Now add the fractions: 1/R_eq = 1/6 + 2/6 = 3/6.
Step 6: To find R_eq, take the reciprocal of 3/6: R_eq = 6/3 = 2Ω.

Parallel Circuit Resistance – Understanding how to calculate the equivalent resistance in a parallel circuit using the formula 1/R_eq = 1/R1 + 1/R2.