If a capacitor is charged to 12V and has a capacitance of 6μF, what is the store

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Question: If a capacitor is charged to 12V and has a capacitance of 6μF, what is the stored energy? (2022)

Options:

Correct Answer: 0.432 mJ

Solution:

Energy = 0.5 × C × V² = 0.5 × 6 × 10^-6 × 12² = 0.432 mJ.

If a capacitor is charged to 12V and has a capacitance of 6μF, what is the stored energy? (2022)

If a capacitor is charged to 12V and has a capacitance of 6μF, what is the stored energy? (2022)

Step 1: Identify the formula for stored energy in a capacitor, which is Energy = 0.5 × C × V².
Step 2: Identify the values given in the question: C (capacitance) = 6μF and V (voltage) = 12V.
Step 3: Convert the capacitance from microfarads to farads: 6μF = 6 × 10^-6 F.
Step 4: Substitute the values into the formula: Energy = 0.5 × (6 × 10^-6) × (12)².
Step 5: Calculate (12)², which is 144.
Step 6: Multiply 6 × 10^-6 by 144 to get 8.64 × 10^-4.
Step 7: Multiply this result by 0.5 to find the energy: 0.5 × 8.64 × 10^-4 = 4.32 × 10^-4.
Step 8: Convert the energy from joules to millijoules: 4.32 × 10^-4 J = 0.432 mJ.

Capacitance and Energy Storage – The relationship between capacitance, voltage, and the energy stored in a capacitor, expressed by the formula Energy = 0.5 × C × V².