What is the general solution of the equation y'' - 3y' + 2y = 0?
Practice Questions
1 question
Q1
What is the general solution of the equation y'' - 3y' + 2y = 0?
y = C1 e^(x) + C2 e^(2x)
y = C1 e^(2x) + C2 e^(x)
y = C1 e^(3x) + C2 e^(0)
y = C1 e^(0) + C2 e^(3x)
The characteristic equation is r^2 - 3r + 2 = 0, which factors to (r - 1)(r - 2) = 0. Thus, the general solution is y = C1 e^(2x) + C2 e^(x).
Questions & Step-by-step Solutions
1 item
Q
Q: What is the general solution of the equation y'' - 3y' + 2y = 0?
Solution: The characteristic equation is r^2 - 3r + 2 = 0, which factors to (r - 1)(r - 2) = 0. Thus, the general solution is y = C1 e^(2x) + C2 e^(x).
