Question: What is the solution to the equation y\' = 3y + 6?
Options:
y = Ce^(3x) - 2
y = Ce^(3x) + 2
y = 2e^(3x)
y = 3Ce^(x)
Correct Answer: y = Ce^(3x) + 2
Solution:
This is a first-order linear equation. The integrating factor is e^(3x), leading to the solution y = Ce^(3x) + 2.
What is the solution to the equation y' = 3y + 6?
Practice Questions
Q1
What is the solution to the equation y' = 3y + 6?
y = Ce^(3x) - 2
y = Ce^(3x) + 2
y = 2e^(3x)
y = 3Ce^(x)
Questions & Step-by-Step Solutions
What is the solution to the equation y' = 3y + 6?
Step 1: Identify the equation. We have y' = 3y + 6, which is a first-order linear differential equation.
Step 2: Rewrite the equation in standard form. This means we want it to look like y' - 3y = 6.
Step 3: Find the integrating factor. The integrating factor is e^(∫-3 dx) = e^(-3x).
Step 4: Multiply the entire equation by the integrating factor. This gives us e^(-3x) * y' - 3e^(-3x) * y = 6e^(-3x).
Step 5: Recognize that the left side is the derivative of (e^(-3x) * y). So we can write it as d/dx(e^(-3x) * y) = 6e^(-3x).
Step 6: Integrate both sides. The left side integrates to e^(-3x) * y, and the right side integrates to -2e^(-3x) + C, where C is the constant of integration.
Step 7: Solve for y. Multiply both sides by e^(3x) to isolate y: y = Ce^(3x) - 2.
Step 8: Simplify the solution. The final solution is y = Ce^(3x) + 2.
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