What is the minimum value of f(x) = 3x^2 - 12x + 9? (2022)
Practice Questions
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What is the minimum value of f(x) = 3x^2 - 12x + 9? (2022)
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The vertex occurs at x = 2. f(2) = 3(2^2) - 12(2) + 9 = 0.
Questions & Step-by-step Solutions
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Q
Q: What is the minimum value of f(x) = 3x^2 - 12x + 9? (2022)
Solution: The vertex occurs at x = 2. f(2) = 3(2^2) - 12(2) + 9 = 0.
Steps: 7
Step 1: Identify the function we need to analyze, which is f(x) = 3x^2 - 12x + 9.
Step 2: Recognize that this is a quadratic function in the form of ax^2 + bx + c, where a = 3, b = -12, and c = 9.
Step 3: To find the minimum value, we need to find the vertex of the parabola. The x-coordinate of the vertex can be found using the formula x = -b/(2a).
Step 4: Substitute the values of a and b into the formula: x = -(-12)/(2*3) = 12/6 = 2.
Step 5: Now that we have the x-coordinate of the vertex (x = 2), we need to find the corresponding y-coordinate by substituting x back into the function: f(2) = 3(2^2) - 12(2) + 9.
