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Find the length of the diagonal of a rectangular box with dimensions 2, 3, and 6
Find the length of the diagonal of a rectangular box with dimensions 2, 3, and 6. (2023)
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Practice Questions
1 question
Q1
Find the length of the diagonal of a rectangular box with dimensions 2, 3, and 6. (2023)
√49
√36
√45
√50
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Diagonal = √(2² + 3² + 6²) = √(4 + 9 + 36) = √49 = 7.
Questions & Step-by-step Solutions
1 item
Q
Q: Find the length of the diagonal of a rectangular box with dimensions 2, 3, and 6. (2023)
Solution:
Diagonal = √(2² + 3² + 6²) = √(4 + 9 + 36) = √49 = 7.
Steps: 7
Show Steps
Step 1: Identify the dimensions of the rectangular box. They are 2, 3, and 6.
Step 2: Write down the formula for the diagonal of a rectangular box: Diagonal = √(length² + width² + height²).
Step 3: Substitute the dimensions into the formula: Diagonal = √(2² + 3² + 6²).
Step 4: Calculate each square: 2² = 4, 3² = 9, and 6² = 36.
Step 5: Add the squared values together: 4 + 9 + 36 = 49.
Step 6: Take the square root of the sum: √49 = 7.
Step 7: Conclude that the length of the diagonal of the rectangular box is 7.
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