In a concentration cell, if the concentration of one half-cell is 0.1 M and the

In a concentration cell, if the concentration of one half-cell is 0.1 M and the other is 1 M, what is the cell potential?

In a concentration cell, if the concentration of one half-cell is 0.1 M and the other is 1 M, what is the cell potential?

Step 1: Identify the concentrations of the two half-cells. One half-cell has a concentration of 0.1 M and the other has a concentration of 1 M.
Step 2: Write down the Nernst equation: E = (0.0591/n) log([C1/C2]).
Step 3: Determine the value of n, which is the number of electrons transferred in the reaction. For this example, n = 1.
Step 4: Substitute the concentrations into the equation. C1 is the lower concentration (0.1 M) and C2 is the higher concentration (1 M).
Step 5: Calculate the ratio [C1/C2], which is 0.1 M / 1 M = 0.1.
Step 6: Take the logarithm of the ratio: log(0.1). This equals -1.
Step 7: Substitute the values into the Nernst equation: E = (0.0591/1) * (-1).
Step 8: Calculate the cell potential: E = -0.0591 V.

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