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In a first-order reaction, if the concentration of reactant decreases from 0.8 M

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Question: In a first-order reaction, if the concentration of reactant decreases from 0.8 M to 0.2 M in 20 minutes, what is the rate constant? (2022)

Options:

  1. 0.0347 min⁻¹
  2. 0.0693 min⁻¹
  3. 0.1 min⁻¹
  4. 0.2 min⁻¹

Correct Answer: 0.0347 min⁻¹

Solution:

Using the first-order rate equation, k = (ln[A₀] - ln[A]) / t. Here, k = (ln(0.8) - ln(0.2)) / 20 = 0.0347 min⁻¹.

In a first-order reaction, if the concentration of reactant decreases from 0.8 M

Practice Questions

Q1
In a first-order reaction, if the concentration of reactant decreases from 0.8 M to 0.2 M in 20 minutes, what is the rate constant? (2022)
  1. 0.0347 min⁻¹
  2. 0.0693 min⁻¹
  3. 0.1 min⁻¹
  4. 0.2 min⁻¹

Questions & Step-by-Step Solutions

In a first-order reaction, if the concentration of reactant decreases from 0.8 M to 0.2 M in 20 minutes, what is the rate constant? (2022)
  • Step 1: Identify the initial concentration of the reactant, A₀, which is 0.8 M.
  • Step 2: Identify the final concentration of the reactant, A, which is 0.2 M.
  • Step 3: Identify the time period, t, which is 20 minutes.
  • Step 4: Use the first-order rate equation: k = (ln[A₀] - ln[A]) / t.
  • Step 5: Calculate ln(0.8) and ln(0.2).
  • Step 6: Substitute the values into the equation: k = (ln(0.8) - ln(0.2)) / 20.
  • Step 7: Perform the calculation to find k.
  • First-Order Reaction Kinetics – Understanding the relationship between concentration, time, and the rate constant in first-order reactions.
  • Natural Logarithm Application – Applying natural logarithms to calculate the change in concentration over time.
  • Rate Constant Calculation – Using the appropriate formula to derive the rate constant from concentration data.
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