A 2 kg object is thrown upwards with a velocity of 10 m/s. What is its maximum h

A 2 kg object is thrown upwards with a velocity of 10 m/s. What is its maximum height? (g = 9.8 m/s²)

A 2 kg object is thrown upwards with a velocity of 10 m/s. What is its maximum height? (g = 9.8 m/s²)

Step 1: Identify the initial velocity (u) of the object, which is given as 10 m/s.
Step 2: Recognize that at the maximum height, the final velocity (v) will be 0 m/s.
Step 3: Use the formula v² = u² - 2gh to find the maximum height (h).
Step 4: Substitute the values into the formula: 0 = (10)² - 2 * 9.8 * h.
Step 5: Calculate (10)², which is 100.
Step 6: Rewrite the equation: 0 = 100 - 19.6h.
Step 7: Rearrange the equation to solve for h: 19.6h = 100.
Step 8: Divide both sides by 19.6 to find h: h = 100 / 19.6.
Step 9: Calculate the value of h, which is approximately 5.1 m.

Kinematics – The study of motion, particularly the equations that describe the relationship between velocity, acceleration, and displacement.
Energy Conservation – Understanding that the kinetic energy of the object is converted into potential energy at the maximum height.