A 10 kg object is lifted to a height of 5 m. What is the work done against gravi
Practice Questions
Q1
A 10 kg object is lifted to a height of 5 m. What is the work done against gravity?
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Questions & Step-by-Step Solutions
A 10 kg object is lifted to a height of 5 m. What is the work done against gravity?
Correct Answer: 490 J
Step 1: Identify the mass of the object. In this case, the mass (m) is 10 kg.
Step 2: Identify the height to which the object is lifted. Here, the height (h) is 5 m.
Step 3: Identify the acceleration due to gravity. This is approximately 9.8 m/s².
Step 4: Use the formula for work done against gravity, which is Work = m * g * h.
Step 5: Substitute the values into the formula: Work = 10 kg * 9.8 m/s² * 5 m.
Step 6: Calculate the result: 10 * 9.8 * 5 = 490 J.
Step 7: Conclude that the work done against gravity is 490 Joules.
Work Done Against Gravity – The work done against gravity is calculated using the formula W = mgh, where W is work, m is mass, g is the acceleration due to gravity, and h is the height.
