What is the final temperature when 200 g of water at 90°C is mixed with 300 g of
Practice Questions
Q1
What is the final temperature when 200 g of water at 90°C is mixed with 300 g of water at 30°C?
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Questions & Step-by-Step Solutions
What is the final temperature when 200 g of water at 90°C is mixed with 300 g of water at 30°C?
Step 1: Identify the masses and temperatures of the two water samples. We have 200 g of water at 90°C (m1 = 200 g, T1 = 90°C) and 300 g of water at 30°C (m2 = 300 g, T2 = 30°C).
Step 2: Write down the formula to find the final temperature (Tf) when two masses of water are mixed: m1*T1 + m2*T2 = (m1 + m2)*Tf.
Step 3: Substitute the values into the formula: 200*90 + 300*30 = (200 + 300)*Tf.
Step 4: Calculate the left side: 200*90 = 18000 and 300*30 = 9000. So, 18000 + 9000 = 27000.
Step 5: Now we have: 27000 = (200 + 300)*Tf, which simplifies to 27000 = 500*Tf.
Step 6: To find Tf, divide both sides by 500: Tf = 27000 / 500.
