If 1 kg of water is heated from 20°C to 100°C, how much heat is absorbed? (Specific heat of water = 4.2 J/g°C)

Practice Questions

1 question
Q1
If 1 kg of water is heated from 20°C to 100°C, how much heat is absorbed? (Specific heat of water = 4.2 J/g°C)
  1. 3360 J
  2. 4000 J
  3. 4200 J
  4. 4800 J

Questions & Step-by-step Solutions

1 item
Q
Q: If 1 kg of water is heated from 20°C to 100°C, how much heat is absorbed? (Specific heat of water = 4.2 J/g°C)
Solution: Q = m*c*ΔT = 1000 g * 4.2 J/g°C * (100°C - 20°C) = 4200 J.
Steps: 0

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