What is the heat required to raise the temperature of 250 g of aluminum from 25°

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Question: What is the heat required to raise the temperature of 250 g of aluminum from 25°C to 75°C? (Specific heat of aluminum = 0.9 J/g°C)

Options:

Correct Answer: 4500 J

Solution:

Q = m*c*ΔT = 250 g * 0.9 J/g°C * (75°C - 25°C) = 4500 J.

What is the heat required to raise the temperature of 250 g of aluminum from 25°C to 75°C? (Specific heat of aluminum = 0.9 J/g°C)

What is the heat required to raise the temperature of 250 g of aluminum from 25°C to 75°C? (Specific heat of aluminum = 0.9 J/g°C)

Step 1: Identify the mass of aluminum. In this case, it is 250 grams.
Step 2: Identify the specific heat of aluminum. It is given as 0.9 J/g°C.
Step 3: Determine the initial temperature (T1) and final temperature (T2). Here, T1 is 25°C and T2 is 75°C.
Step 4: Calculate the change in temperature (ΔT) using the formula ΔT = T2 - T1. So, ΔT = 75°C - 25°C = 50°C.
Step 5: Use the formula for heat (Q) required: Q = m * c * ΔT.
Step 6: Substitute the values into the formula: Q = 250 g * 0.9 J/g°C * 50°C.
Step 7: Perform the multiplication: 250 * 0.9 = 225, then 225 * 50 = 11250 J.
Step 8: The final answer is the heat required, which is 11250 J.

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