What is the torque about a pivot if a force of 12 N is applied at a distance of 0.25 m at an angle of 90 degrees?

Practice Questions

1 question
Q1
What is the torque about a pivot if a force of 12 N is applied at a distance of 0.25 m at an angle of 90 degrees?
  1. 3 Nm
  2. 6 Nm
  3. 12 Nm
  4. 24 Nm

Questions & Step-by-step Solutions

1 item
Q
Q: What is the torque about a pivot if a force of 12 N is applied at a distance of 0.25 m at an angle of 90 degrees?
Solution: Torque = Force × Distance = 12 N × 0.25 m = 3 Nm.
Steps: 0

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