What is the torque about a pivot if a force of 12 N is applied at a distance of

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Question: What is the torque about a pivot if a force of 12 N is applied at a distance of 0.25 m at an angle of 90 degrees?

Options:

Correct Answer: 12 Nm

Solution:

Torque = Force × Distance = 12 N × 0.25 m = 3 Nm.

What is the torque about a pivot if a force of 12 N is applied at a distance of 0.25 m at an angle of 90 degrees?

What is the torque about a pivot if a force of 12 N is applied at a distance of 0.25 m at an angle of 90 degrees?

Step 1: Identify the force applied. In this case, the force is 12 N.
Step 2: Identify the distance from the pivot point where the force is applied. Here, the distance is 0.25 m.
Step 3: Check the angle at which the force is applied. The angle is 90 degrees, which means the force is applied perpendicularly.
Step 4: Use the formula for torque, which is Torque = Force × Distance.
Step 5: Substitute the values into the formula: Torque = 12 N × 0.25 m.
Step 6: Calculate the result: 12 N × 0.25 m = 3 Nm.

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