My Learning Cart
?
Categories
Account

In a seesaw, if one child exerts a force of 30 N at a distance of 1.5 m from the

₹0.0
Login to Download
  • 📥 Instant PDF Download
  • ♾ Lifetime Access
  • 🛡 Secure & Original Content

What’s inside this PDF?

Question: In a seesaw, if one child exerts a force of 30 N at a distance of 1.5 m from the pivot, what is the torque produced by this child?

Options:

  1. 15 Nm
  2. 30 Nm
  3. 45 Nm
  4. 60 Nm

Correct Answer: 45 Nm

Solution: 

Torque (τ) = F × r = 30 N × 1.5 m = 45 Nm.

In a seesaw, if one child exerts a force of 30 N at a distance of 1.5 m from the

Practice Questions

Q1
In a seesaw, if one child exerts a force of 30 N at a distance of 1.5 m from the pivot, what is the torque produced by this child?
  1. 15 Nm
  2. 30 Nm
  3. 45 Nm
  4. 60 Nm

Questions & Step-by-Step Solutions

In a seesaw, if one child exerts a force of 30 N at a distance of 1.5 m from the pivot, what is the torque produced by this child?
  • Step 1: Identify the force exerted by the child, which is 30 N.
  • Step 2: Identify the distance from the pivot to where the force is applied, which is 1.5 m.
  • Step 3: Use the formula for torque, which is Torque (Ï„) = Force (F) × Distance (r).
  • Step 4: Substitute the values into the formula: Ï„ = 30 N × 1.5 m.
  • Step 5: Calculate the result: 30 N × 1.5 m = 45 Nm.
  • Step 6: Conclude that the torque produced by the child is 45 Nm.
  • Torque – Torque is the rotational equivalent of linear force, calculated as the product of the force applied and the distance from the pivot point.
Soulshift Feedback ×

On a scale of 0–10, how likely are you to recommend The Soulshift Academy?

Not likely Very likely
Home Practice Performance eBooks