A force of 50 N is applied at a distance of 0.5 m from the pivot at an angle of
Practice Questions
Q1
A force of 50 N is applied at a distance of 0.5 m from the pivot at an angle of 60 degrees. What is the torque?
25 Nm
43.3 Nm
50 Nm
0 Nm
Questions & Step-by-Step Solutions
A force of 50 N is applied at a distance of 0.5 m from the pivot at an angle of 60 degrees. What is the torque?
Step 1: Identify the values given in the problem. We have a force (F) of 50 N, a distance (r) of 0.5 m from the pivot, and an angle (θ) of 60 degrees.
Step 2: Recall the formula for torque (τ), which is τ = F × r × sin(θ).
Step 3: Substitute the values into the formula. We have τ = 50 N × 0.5 m × sin(60°).
Step 4: Calculate sin(60°). The value of sin(60°) is √3/2.
Step 5: Substitute sin(60°) into the equation. Now we have τ = 50 N × 0.5 m × (√3/2).
Step 6: Calculate the multiplication. First, calculate 50 N × 0.5 m = 25 N·m.
Step 7: Now multiply 25 N·m by (√3/2). This gives us τ = 25 N·m × (√3/2).
Step 8: Calculate the final value. 25 N·m × (√3/2) = 25 N·m × 0.866 = 43.3 Nm.
Torque Calculation – Torque is calculated using the formula τ = F × r × sin(θ), where F is the force applied, r is the distance from the pivot, and θ is the angle between the force and the lever arm.
