If a force of 15 N is applied at an angle of 30 degrees to the lever arm of leng

Practice Questions

Q1
If a force of 15 N is applied at an angle of 30 degrees to the lever arm of length 1 m, what is the torque about the pivot?
  1. 7.5 Nm
  2. 15 Nm
  3. 12.99 Nm
  4. 10 Nm

Questions & Step-by-Step Solutions

If a force of 15 N is applied at an angle of 30 degrees to the lever arm of length 1 m, what is the torque about the pivot?
  • Step 1: Identify the force applied, which is 15 N.
  • Step 2: Identify the length of the lever arm, which is 1 m.
  • Step 3: Identify the angle at which the force is applied, which is 30 degrees.
  • Step 4: Use the formula for torque: Torque (τ) = Force (F) × Length of lever arm (r) × sin(angle).
  • Step 5: Substitute the values into the formula: τ = 15 N × 1 m × sin(30°).
  • Step 6: Calculate sin(30°), which is 0.5.
  • Step 7: Multiply the values: τ = 15 N × 1 m × 0.5.
  • Step 8: Calculate the final result: τ = 7.5 Nm.
  • Torque Calculation – Torque is calculated using the formula τ = F × r × sin(θ), where F is the force applied, r is the distance from the pivot, and θ is the angle between the force and the lever arm.
  • Trigonometric Functions – Understanding how to use sine in the context of angles is crucial for calculating torque correctly.
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