A simple harmonic oscillator has a mass of 0.5 kg and a spring constant of 200 N
Practice Questions
Q1
A simple harmonic oscillator has a mass of 0.5 kg and a spring constant of 200 N/m. What is the angular frequency of the oscillator?
10 rad/s
20 rad/s
5 rad/s
15 rad/s
Questions & Step-by-Step Solutions
A simple harmonic oscillator has a mass of 0.5 kg and a spring constant of 200 N/m. What is the angular frequency of the oscillator?
Step 1: Identify the values given in the problem. The mass (m) is 0.5 kg and the spring constant (k) is 200 N/m.
Step 2: Write down the formula for angular frequency (ω) of a simple harmonic oscillator, which is ω = √(k/m).
Step 3: Substitute the values of k and m into the formula. This means you will calculate √(200/0.5).
Step 4: Calculate the value of 200 divided by 0.5. This equals 400.
Step 5: Now, take the square root of 400. The square root of 400 is 20.
Step 6: Therefore, the angular frequency (ω) is 20 rad/s.
Angular Frequency – The angular frequency of a simple harmonic oscillator is determined by the mass of the object and the spring constant, calculated using the formula ω = √(k/m).
Simple Harmonic Motion – Understanding the principles of simple harmonic motion, including the relationship between mass, spring constant, and angular frequency.