A simple harmonic oscillator has a mass of 0.5 kg and a spring constant of 200 N

Practice Questions

Q1
A simple harmonic oscillator has a mass of 0.5 kg and a spring constant of 200 N/m. What is the angular frequency of the oscillator?
  1. 10 rad/s
  2. 20 rad/s
  3. 5 rad/s
  4. 15 rad/s

Questions & Step-by-Step Solutions

A simple harmonic oscillator has a mass of 0.5 kg and a spring constant of 200 N/m. What is the angular frequency of the oscillator?
  • Step 1: Identify the values given in the problem. The mass (m) is 0.5 kg and the spring constant (k) is 200 N/m.
  • Step 2: Write down the formula for angular frequency (ω) of a simple harmonic oscillator, which is ω = √(k/m).
  • Step 3: Substitute the values of k and m into the formula. This means you will calculate √(200/0.5).
  • Step 4: Calculate the value of 200 divided by 0.5. This equals 400.
  • Step 5: Now, take the square root of 400. The square root of 400 is 20.
  • Step 6: Therefore, the angular frequency (ω) is 20 rad/s.
  • Angular Frequency – The angular frequency of a simple harmonic oscillator is determined by the mass of the object and the spring constant, calculated using the formula ω = √(k/m).
  • Simple Harmonic Motion – Understanding the principles of simple harmonic motion, including the relationship between mass, spring constant, and angular frequency.
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