What is the period of a pendulum that is 1 meter long?

₹0.0

Question: What is the period of a pendulum that is 1 meter long?

Options:

Correct Answer: 2 s

Solution:

The period T of a simple pendulum is given by T = 2π√(L/g). For L = 1 m and g ≈ 9.8 m/s², T = 2π√(1/9.8) ≈ 2 s.

What is the period of a pendulum that is 1 meter long?

What is the period of a pendulum that is 1 meter long?

Step 1: Understand the formula for the period of a pendulum, which is T = 2π√(L/g).
Step 2: Identify the length of the pendulum (L). In this case, L = 1 meter.
Step 3: Know the value of g, which is the acceleration due to gravity. It is approximately 9.8 m/s².
Step 4: Substitute the values into the formula: T = 2π√(1/9.8).
Step 5: Calculate the value inside the square root: 1/9.8 ≈ 0.10204.
Step 6: Find the square root of 0.10204, which is approximately 0.319.
Step 7: Multiply this value by 2π (approximately 6.283): T ≈ 6.283 * 0.319.
Step 8: Calculate the final result: T ≈ 2 seconds.

No concepts available.