In a double-slit experiment, if the wavelength of light is 600 nm and the distan
Practice Questions
Q1
In a double-slit experiment, if the wavelength of light is 600 nm and the distance between the slits is 0.5 mm, what is the fringe width if the screen is 1 m away?
0.12 mm
0.3 mm
0.6 mm
0.5 mm
Questions & Step-by-Step Solutions
In a double-slit experiment, if the wavelength of light is 600 nm and the distance between the slits is 0.5 mm, what is the fringe width if the screen is 1 m away?
Step 1: Identify the given values from the problem. The wavelength of light (λ) is 600 nm, the distance between the slits (d) is 0.5 mm, and the distance from the slits to the screen (D) is 1 m.
Step 2: Convert the units to meters for consistency. 600 nm = 600 x 10^-9 m and 0.5 mm = 0.5 x 10^-3 m.
Step 3: Use the formula for fringe width (β): β = λD/d.
Step 4: Substitute the values into the formula: β = (600 x 10^-9 m)(1 m) / (0.5 x 10^-3 m).
Step 5: Calculate the numerator: 600 x 10^-9 m * 1 m = 600 x 10^-9 m.
Step 6: Calculate the denominator: 0.5 x 10^-3 m = 0.0005 m.
Step 7: Divide the numerator by the denominator: β = (600 x 10^-9 m) / (0.0005 m).
Step 8: Perform the division: β = 0.12 x 10^-3 m = 0.12 mm.
