A beam of light passes through a prism with a refractive index of 1.5. If the an
Practice Questions
Q1
A beam of light passes through a prism with a refractive index of 1.5. If the angle of the prism is 60 degrees, what is the angle of minimum deviation?
30 degrees
45 degrees
60 degrees
75 degrees
Questions & Step-by-Step Solutions
A beam of light passes through a prism with a refractive index of 1.5. If the angle of the prism is 60 degrees, what is the angle of minimum deviation?
Step 1: Identify the given values. The refractive index (n) of the prism is 1.5 and the angle of the prism (A) is 60 degrees.
Step 2: Understand the formula for the angle of minimum deviation (D) for a prism, which is D = A(n - 1).
Step 3: Substitute the values into the formula. Here, A = 60 degrees and n = 1.5.
Step 4: Calculate (n - 1). This is 1.5 - 1 = 0.5.
Step 5: Multiply the angle of the prism (A) by (n - 1). This is 60 degrees * 0.5 = 30 degrees.
Step 6: Conclude that the angle of minimum deviation (D) is 30 degrees.
Refraction and Prism Angles – Understanding how light bends when passing through different media and the relationship between the angle of the prism and the angle of minimum deviation.
Refractive Index – Knowledge of how the refractive index affects the bending of light and its calculation in relation to the prism's angle.
Minimum Deviation Formula – Application of the formula D = A(n - 1) to find the angle of minimum deviation for a prism.
