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A beam of light passes through a prism with a refractive index of 1.5. If the an

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Question: A beam of light passes through a prism with a refractive index of 1.5. If the angle of the prism is 60 degrees, what is the angle of minimum deviation?

Options:

  1. 30 degrees
  2. 45 degrees
  3. 60 degrees
  4. 75 degrees

Correct Answer: 30 degrees

Solution: 

For a prism, the angle of minimum deviation D is given by D = A(n - 1), where A is the angle of the prism. Here, D = 60(1.5 - 1) = 30 degrees.

A beam of light passes through a prism with a refractive index of 1.5. If the an

Practice Questions

Q1
A beam of light passes through a prism with a refractive index of 1.5. If the angle of the prism is 60 degrees, what is the angle of minimum deviation?
  1. 30 degrees
  2. 45 degrees
  3. 60 degrees
  4. 75 degrees

Questions & Step-by-Step Solutions

A beam of light passes through a prism with a refractive index of 1.5. If the angle of the prism is 60 degrees, what is the angle of minimum deviation?
  • Step 1: Identify the given values. The refractive index (n) of the prism is 1.5 and the angle of the prism (A) is 60 degrees.
  • Step 2: Understand the formula for the angle of minimum deviation (D) for a prism, which is D = A(n - 1).
  • Step 3: Substitute the values into the formula. Here, A = 60 degrees and n = 1.5.
  • Step 4: Calculate (n - 1). This is 1.5 - 1 = 0.5.
  • Step 5: Multiply the angle of the prism (A) by (n - 1). This is 60 degrees * 0.5 = 30 degrees.
  • Step 6: Conclude that the angle of minimum deviation (D) is 30 degrees.
  • Refraction and Prism Angles – Understanding how light bends when passing through different media and the relationship between the angle of the prism and the angle of minimum deviation.
  • Refractive Index – Knowledge of how the refractive index affects the bending of light and its calculation in relation to the prism's angle.
  • Minimum Deviation Formula – Application of the formula D = A(n - 1) to find the angle of minimum deviation for a prism.
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