A solenoid with a length of 1 m and a cross-sectional area of 0.01 m² carries a
Practice Questions
Q1
A solenoid with a length of 1 m and a cross-sectional area of 0.01 m² carries a current of 5 A. If the magnetic field inside the solenoid is uniform, what is the magnetic field strength?
0.1 T
0.2 T
0.5 T
1 T
Questions & Step-by-Step Solutions
A solenoid with a length of 1 m and a cross-sectional area of 0.01 m² carries a current of 5 A. If the magnetic field inside the solenoid is uniform, what is the magnetic field strength?
Step 1: Identify the formula for the magnetic field inside a solenoid, which is B = μ₀ * (N/L) * I.
Step 2: Understand that μ₀ (the permeability of free space) is a constant value, approximately equal to 4π × 10^-7 T*m/A.
Step 3: Note that N is the number of turns of the solenoid and L is the length of the solenoid. In this case, we will assume N/L = 1 for simplicity.
Step 4: Substitute the values into the formula. Since N/L = 1, the formula simplifies to B = μ₀ * I.
Step 5: Substitute I (the current) with 5 A into the simplified formula: B = (4π × 10^-7 T*m/A) * (5 A).
Step 6: Calculate the magnetic field strength: B = 4π × 10^-7 * 5 = 0.5 T.
Magnetic Field in a Solenoid – The magnetic field strength (B) inside a solenoid is calculated using the formula B = μ₀ * (N/L) * I, where μ₀ is the permeability of free space, N is the number of turns, L is the length of the solenoid, and I is the current.
