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A 10 kg object is at rest on a surface. If a force of 30 N is applied, what is t
A 10 kg object is at rest on a surface. If a force of 30 N is applied, what is the object's acceleration assuming the friction is negligible?
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Practice Questions
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Q1
A 10 kg object is at rest on a surface. If a force of 30 N is applied, what is the object's acceleration assuming the friction is negligible?
1 m/s²
2 m/s²
3 m/s²
4 m/s²
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Using F = ma, acceleration a = F/m = 30 N / 10 kg = 3 m/s².
Questions & Step-by-step Solutions
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Q
Q: A 10 kg object is at rest on a surface. If a force of 30 N is applied, what is the object's acceleration assuming the friction is negligible?
Solution:
Using F = ma, acceleration a = F/m = 30 N / 10 kg = 3 m/s².
Steps: 6
Show Steps
Step 1: Identify the mass of the object. The mass is given as 10 kg.
Step 2: Identify the force applied to the object. The force is given as 30 N.
Step 3: Recall the formula for acceleration, which is a = F/m, where F is the force and m is the mass.
Step 4: Substitute the values into the formula: a = 30 N / 10 kg.
Step 5: Calculate the acceleration: 30 N divided by 10 kg equals 3 m/s².
Step 6: Conclude that the object's acceleration is 3 m/s².
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