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A 10 kg object is at rest on a surface. If a force of 30 N is applied, what is t

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Question: A 10 kg object is at rest on a surface. If a force of 30 N is applied, what is the object\'s acceleration assuming the friction is negligible?

Options:

  1. 1 m/s²
  2. 2 m/s²
  3. 3 m/s²
  4. 4 m/s²

Correct Answer: 3 m/s²

Solution: 

Using F = ma, acceleration a = F/m = 30 N / 10 kg = 3 m/s².

A 10 kg object is at rest on a surface. If a force of 30 N is applied, what is t

Practice Questions

Q1
A 10 kg object is at rest on a surface. If a force of 30 N is applied, what is the object's acceleration assuming the friction is negligible?
  1. 1 m/s²
  2. 2 m/s²
  3. 3 m/s²
  4. 4 m/s²

Questions & Step-by-Step Solutions

A 10 kg object is at rest on a surface. If a force of 30 N is applied, what is the object's acceleration assuming the friction is negligible?
  • Step 1: Identify the mass of the object. The mass is given as 10 kg.
  • Step 2: Identify the force applied to the object. The force is given as 30 N.
  • Step 3: Recall the formula for acceleration, which is a = F/m, where F is the force and m is the mass.
  • Step 4: Substitute the values into the formula: a = 30 N / 10 kg.
  • Step 5: Calculate the acceleration: 30 N divided by 10 kg equals 3 m/s².
  • Step 6: Conclude that the object's acceleration is 3 m/s².
  • Newton's Second Law of Motion – This law states that the acceleration of an object is directly proportional to the net force acting on it and inversely proportional to its mass.
  • Force and Acceleration Relationship – Understanding how to calculate acceleration using the formula a = F/m, where F is the net force and m is the mass.
  • Negligible Friction Assumption – The problem assumes that friction is negligible, simplifying the calculation of acceleration.
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