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A 1 kg ball is thrown vertically upwards with a speed of 20 m/s. What is the max

Practice Questions

Q1
A 1 kg ball is thrown vertically upwards with a speed of 20 m/s. What is the maximum height it reaches? (Assume g = 10 m/s²)
  1. 20 m
  2. 30 m
  3. 40 m
  4. 50 m

Questions & Step-by-Step Solutions

A 1 kg ball is thrown vertically upwards with a speed of 20 m/s. What is the maximum height it reaches? (Assume g = 10 m/s²)
  • Step 1: Identify the initial speed of the ball, which is 20 m/s.
  • Step 2: Identify the acceleration due to gravity, which is g = 10 m/s².
  • Step 3: Use the formula for maximum height, h = v² / (2g).
  • Step 4: Substitute the values into the formula: h = (20 m/s)² / (2 * 10 m/s²).
  • Step 5: Calculate (20 m/s)², which equals 400 m²/s².
  • Step 6: Calculate 2 * 10 m/s², which equals 20 m/s².
  • Step 7: Divide 400 m²/s² by 20 m/s² to find h: 400 / 20 = 20 m.
  • Step 8: Conclude that the maximum height the ball reaches is 20 meters.
  • Kinematics – The study of motion, specifically how objects move under the influence of forces.
  • Energy Conservation – The principle that energy cannot be created or destroyed, only transformed from one form to another.
  • Gravitational Acceleration – The acceleration due to gravity, which affects the motion of objects in free fall.
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