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A 4 kg object is moving in a circular path of radius 2 m with a speed of 6 m/s.
A 4 kg object is moving in a circular path of radius 2 m with a speed of 6 m/s. What is the centripetal force acting on it?
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A 4 kg object is moving in a circular path of radius 2 m with a speed of 6 m/s. What is the centripetal force acting on it?
9 N
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18 N
24 N
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Centripetal force F = mv²/r = 4 kg * (6 m/s)² / 2 m = 72 N / 2 = 36 N.
Questions & Step-by-step Solutions
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Q
Q: A 4 kg object is moving in a circular path of radius 2 m with a speed of 6 m/s. What is the centripetal force acting on it?
Solution:
Centripetal force F = mv²/r = 4 kg * (6 m/s)² / 2 m = 72 N / 2 = 36 N.
Steps: 8
Show Steps
Step 1: Identify the mass of the object. The mass (m) is given as 4 kg.
Step 2: Identify the speed of the object. The speed (v) is given as 6 m/s.
Step 3: Identify the radius of the circular path. The radius (r) is given as 2 m.
Step 4: Use the formula for centripetal force: F = mv²/r.
Step 5: Calculate v² (the speed squared): (6 m/s)² = 36 m²/s².
Step 6: Multiply the mass by v²: 4 kg * 36 m²/s² = 144 kg·m²/s².
Step 7: Divide the result by the radius: 144 kg·m²/s² / 2 m = 72 N.
Step 8: The centripetal force is 72 N.
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