A 3 kg mass is attached to a spring with a spring constant of 200 N/m. What is t
Practice Questions
Q1
A 3 kg mass is attached to a spring with a spring constant of 200 N/m. What is the maximum force exerted by the spring when stretched?
100 N
200 N
300 N
600 N
Questions & Step-by-Step Solutions
A 3 kg mass is attached to a spring with a spring constant of 200 N/m. What is the maximum force exerted by the spring when stretched?
Correct Answer: 200 N
Step 1: Identify the spring constant (k). In this case, k = 200 N/m.
Step 2: Determine the maximum stretch (x) of the spring. Here, we assume x = 1 m.
Step 3: Use the formula for force exerted by the spring, which is F = k * x.
Step 4: Substitute the values into the formula: F = 200 N/m * 1 m.
Step 5: Calculate the force: F = 200 N.
Hooke's Law – The relationship between the force exerted by a spring and its displacement from the equilibrium position, expressed as F = kx, where F is the force, k is the spring constant, and x is the displacement.
Maximum Stretch – Understanding that the maximum force occurs at the maximum displacement of the spring.
