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A 5 kg object is dropped from a height. What is the force acting on it just befo

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Question: A 5 kg object is dropped from a height. What is the force acting on it just before it hits the ground? (Assume g = 9.8 m/s²)

Options:

  1. 5 N
  2. 9.8 N
  3. 49 N
  4. 0 N

Correct Answer: 49 N

Solution: 

The force acting on the object is its weight, F = mg = 5 kg * 9.8 m/s² = 49 N.

A 5 kg object is dropped from a height. What is the force acting on it just befo

Practice Questions

Q1
A 5 kg object is dropped from a height. What is the force acting on it just before it hits the ground? (Assume g = 9.8 m/s²)
  1. 5 N
  2. 9.8 N
  3. 49 N
  4. 0 N

Questions & Step-by-Step Solutions

A 5 kg object is dropped from a height. What is the force acting on it just before it hits the ground? (Assume g = 9.8 m/s²)
  • Step 1: Identify the mass of the object. In this case, the mass is 5 kg.
  • Step 2: Identify the acceleration due to gravity (g). Here, g is 9.8 m/s².
  • Step 3: Use the formula for weight (force) which is F = mg.
  • Step 4: Substitute the values into the formula: F = 5 kg * 9.8 m/s².
  • Step 5: Calculate the result: F = 49 N.
  • Weight Calculation – The weight of an object is calculated using the formula F = mg, where m is the mass and g is the acceleration due to gravity.
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