A 4 kg object is moving in a circular path of radius 2 m with a speed of 6 m/s. What is the centripetal force acting on the object?

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Q: A 4 kg object is moving in a circular path of radius 2 m with a speed of 6 m/s. What is the centripetal force acting on the object?

Solution: Centripetal force F = mv²/r = 4 kg * (6 m/s)² / 2 m = 4 * 36 / 2 = 72 N / 2 = 36 N.

Steps: 9

Step 1: Identify the mass of the object. The mass (m) is given as 4 kg.
Step 2: Identify the speed of the object. The speed (v) is given as 6 m/s.
Step 3: Identify the radius of the circular path. The radius (r) is given as 2 m.
Step 4: Use the formula for centripetal force, which is F = mv²/r.
Step 5: Substitute the values into the formula: F = 4 kg * (6 m/s)² / 2 m.
Step 6: Calculate (6 m/s)², which is 36 m²/s².
Step 7: Multiply 4 kg by 36 m²/s² to get 144 kg*m²/s².
Step 8: Divide 144 kg*m²/s² by 2 m to find the centripetal force: 144 / 2 = 72 N.
Step 9: The final answer is 72 N.