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A particle moves in a circular path of radius 10 m with a speed of 5 m/s. What i
A particle moves in a circular path of radius 10 m with a speed of 5 m/s. What is the period of motion?
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Q1
A particle moves in a circular path of radius 10 m with a speed of 5 m/s. What is the period of motion?
2π s
4π s
10 s
20 s
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Period T = (2πr)/v = (2π * 10)/5 = 4π s.
Questions & Step-by-step Solutions
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Q
Q: A particle moves in a circular path of radius 10 m with a speed of 5 m/s. What is the period of motion?
Solution:
Period T = (2πr)/v = (2π * 10)/5 = 4π s.
Steps: 7
Show Steps
Step 1: Identify the radius of the circular path. In this case, the radius (r) is 10 meters.
Step 2: Identify the speed of the particle. Here, the speed (v) is 5 meters per second.
Step 3: Use the formula for the period (T) of motion in circular motion, which is T = (2πr) / v.
Step 4: Substitute the values into the formula. So, T = (2π * 10) / 5.
Step 5: Calculate the numerator: 2π * 10 = 20π.
Step 6: Now divide 20π by 5: 20π / 5 = 4π.
Step 7: The period of motion (T) is 4π seconds.
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