If 1 mole of an ideal gas occupies 22.4 L at STP, what is the volume occupied by

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Question: If 1 mole of an ideal gas occupies 22.4 L at STP, what is the volume occupied by 2 moles at the same conditions?

Options:

Correct Answer: 44.8 L

Solution:

According to Avogadro\'s Law, 2 moles of gas will occupy double the volume, which is 44.8 L at STP.

If 1 mole of an ideal gas occupies 22.4 L at STP, what is the volume occupied by 2 moles at the same conditions?

If 1 mole of an ideal gas occupies 22.4 L at STP, what is the volume occupied by 2 moles at the same conditions?

Step 1: Understand that 1 mole of an ideal gas occupies 22.4 liters at Standard Temperature and Pressure (STP).
Step 2: Recognize that Avogadro's Law states that equal volumes of gases, at the same temperature and pressure, contain an equal number of molecules.
Step 3: Since we have 2 moles of gas, we need to find the volume for 2 moles.
Step 4: Calculate the volume for 2 moles by multiplying the volume of 1 mole (22.4 L) by 2.
Step 5: Perform the calculation: 22.4 L x 2 = 44.8 L.
Step 6: Conclude that 2 moles of the ideal gas will occupy 44.8 liters at STP.

Avogadro's Law – Avogadro's Law states that equal volumes of gases, at the same temperature and pressure, contain an equal number of molecules. This implies that the volume of a gas is directly proportional to the number of moles.