If the mass of the Earth is 6 x 10^24 kg and the radius is 6.4 x 10^6 m, what is

If the mass of the Earth is 6 x 10^24 kg and the radius is 6.4 x 10^6 m, what is the gravitational acceleration at the surface of the Earth?

If the mass of the Earth is 6 x 10^24 kg and the radius is 6.4 x 10^6 m, what is the gravitational acceleration at the surface of the Earth?

Step 1: Identify the formula for gravitational acceleration, which is g = G * M / R².
Step 2: Write down the values you have: G = 6.67 x 10^-11 N m²/kg², M = 6 x 10^24 kg, and R = 6.4 x 10^6 m.
Step 3: Calculate R² (the radius squared). R² = (6.4 x 10^6 m) * (6.4 x 10^6 m).
Step 4: Multiply the mass (M) by the gravitational constant (G). Calculate G * M = (6.67 x 10^-11 N m²/kg²) * (6 x 10^24 kg).
Step 5: Divide the result from Step 4 by the result from Step 3 to find g. g = (G * M) / R².
Step 6: Calculate the final value of g, which should be approximately 9.8 m/s².

Gravitational Acceleration – Understanding the formula for gravitational acceleration and how to apply it using mass and radius.
Units and Constants – Knowledge of the gravitational constant (G) and its units, as well as the conversion of scientific notation.
Physics of Gravity – Application of Newton's law of universal gravitation in calculating gravitational force.