If the electric potential at a point is 300 V and the electric field is uniform, what is the work done in moving a charge of 3 μC to a point where the potential is 600 V?
Practice Questions
1 question
Q1
If the electric potential at a point is 300 V and the electric field is uniform, what is the work done in moving a charge of 3 μC to a point where the potential is 600 V?
0.9 mJ
0.6 mJ
0.3 mJ
1.2 mJ
Work done W = q * ΔV = 3 × 10^-6 C * (600 V - 300 V) = 3 × 10^-6 * 300 = 0.9 mJ.
Questions & Step-by-step Solutions
1 item
Q
Q: If the electric potential at a point is 300 V and the electric field is uniform, what is the work done in moving a charge of 3 μC to a point where the potential is 600 V?
Solution: Work done W = q * ΔV = 3 × 10^-6 C * (600 V - 300 V) = 3 × 10^-6 * 300 = 0.9 mJ.
Steps: 8
Step 1: Identify the initial electric potential (V1) which is 300 V.
Step 2: Identify the final electric potential (V2) which is 600 V.
Step 3: Calculate the change in electric potential (ΔV) by subtracting V1 from V2: ΔV = V2 - V1 = 600 V - 300 V.
Step 4: Calculate ΔV: ΔV = 300 V.
Step 5: Identify the charge (q) which is 3 μC. Convert this to coulombs: 3 μC = 3 × 10^-6 C.
Step 6: Use the formula for work done (W) which is W = q * ΔV.
Step 7: Substitute the values into the formula: W = 3 × 10^-6 C * 300 V.
