What is the work done in moving a charge of 2 μC from a point at 50 V to a point

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Question: What is the work done in moving a charge of 2 μC from a point at 50 V to a point at 100 V?

Options:

Correct Answer: 0.2 mJ

Solution:

Work done W = q * ΔV = 2 × 10^-6 C * (100 V - 50 V) = 2 × 10^-6 * 50 = 0.1 mJ.

What is the work done in moving a charge of 2 μC from a point at 50 V to a point at 100 V?

What is the work done in moving a charge of 2 μC from a point at 50 V to a point at 100 V?

Step 1: Identify the charge being moved, which is 2 μC (microcoulombs). Convert this to coulombs: 2 μC = 2 × 10^-6 C.
Step 2: Identify the initial voltage (V1) and the final voltage (V2). Here, V1 = 50 V and V2 = 100 V.
Step 3: Calculate the change in voltage (ΔV) by subtracting the initial voltage from the final voltage: ΔV = V2 - V1 = 100 V - 50 V = 50 V.
Step 4: Use the formula for work done (W) which is W = q * ΔV, where q is the charge and ΔV is the change in voltage.
Step 5: Substitute the values into the formula: W = 2 × 10^-6 C * 50 V.
Step 6: Calculate the work done: W = 2 × 10^-6 * 50 = 0.1 mJ (millijoules).

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