Question: The gravitational field strength at the surface of a planet is 9.8 N/kg. What is the gravitational potential at the surface if the radius of the planet is 6.4 x 10^6 m?
Options:
Correct Answer: -62.72 x 10^6 J/kg
Solution:
V = -g * r = -9.8 N/kg * 6.4 x 10^6 m = -62.72 x 10^6 J/kg.