A charge of +10μC is placed in a uniform electric field of 500 N/C. What is the

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Question: A charge of +10μC is placed in a uniform electric field of 500 N/C. What is the force acting on the charge?

Options:

Correct Answer: 5 N

Solution:

Force F = qE = (10 × 10^-6 C) * (500 N/C) = 5 N.

A charge of +10μC is placed in a uniform electric field of 500 N/C. What is the force acting on the charge?

A charge of +10μC is placed in a uniform electric field of 500 N/C. What is the force acting on the charge?

Step 1: Identify the charge value. The charge is +10μC (microcoulombs). Convert this to coulombs: 10μC = 10 × 10^-6 C.
Step 2: Identify the strength of the electric field. The electric field is given as 500 N/C (newtons per coulomb).
Step 3: Use the formula for force in an electric field, which is F = qE, where F is the force, q is the charge, and E is the electric field strength.
Step 4: Substitute the values into the formula: F = (10 × 10^-6 C) * (500 N/C).
Step 5: Calculate the force: F = 10 × 500 × 10^-6 = 5000 × 10^-6 = 5 N.
Step 6: Conclude that the force acting on the charge is 5 N.

Electric Force Calculation – The question tests the ability to calculate the force acting on a charge in an electric field using the formula F = qE, where F is the force, q is the charge, and E is the electric field strength.
Units of Measurement – Understanding the units involved (Coulombs for charge and Newtons per Coulomb for electric field) is crucial for correctly applying the formula.