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A charge of +10μC is placed in a uniform electric field of 500 N/C. What is the
A charge of +10μC is placed in a uniform electric field of 500 N/C. What is the force acting on the charge?
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Q1
A charge of +10μC is placed in a uniform electric field of 500 N/C. What is the force acting on the charge?
0.5 N
5 N
50 N
500 N
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Force F = qE = (10 × 10^-6 C) * (500 N/C) = 5 N.
Questions & Step-by-step Solutions
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Q
Q: A charge of +10μC is placed in a uniform electric field of 500 N/C. What is the force acting on the charge?
Solution:
Force F = qE = (10 × 10^-6 C) * (500 N/C) = 5 N.
Steps: 6
Show Steps
Step 1: Identify the charge value. The charge is +10μC (microcoulombs). Convert this to coulombs: 10μC = 10 × 10^-6 C.
Step 2: Identify the strength of the electric field. The electric field is given as 500 N/C (newtons per coulomb).
Step 3: Use the formula for force in an electric field, which is F = qE, where F is the force, q is the charge, and E is the electric field strength.
Step 4: Substitute the values into the formula: F = (10 × 10^-6 C) * (500 N/C).
Step 5: Calculate the force: F = 10 × 500 × 10^-6 = 5000 × 10^-6 = 5 N.
Step 6: Conclude that the force acting on the charge is 5 N.
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