In a Wheatstone bridge, if the ratio of the resistances in one arm is 2:3 and in
Practice Questions
Q1
In a Wheatstone bridge, if the ratio of the resistances in one arm is 2:3 and in the other arm is 4:5, what is the condition for the bridge to be balanced?
2/3 = 4/5
2/3 = 5/4
3/2 = 5/4
3/2 = 4/5
Questions & Step-by-Step Solutions
In a Wheatstone bridge, if the ratio of the resistances in one arm is 2:3 and in the other arm is 4:5, what is the condition for the bridge to be balanced?
Step 1: Understand that a Wheatstone bridge has four resistors arranged in a diamond shape.
Step 2: Identify the two arms of the bridge. Each arm has a pair of resistors.
Step 3: In the first arm, the resistors have a ratio of 2:3. This means if one resistor is 2 ohms, the other is 3 ohms.
Step 4: In the second arm, the resistors have a ratio of 4:5. This means if one resistor is 4 ohms, the other is 5 ohms.
Step 5: To check if the bridge is balanced, we need to compare the ratios of the resistors in both arms.
Step 6: Calculate the ratio for the first arm: 2/3.
Step 7: Calculate the ratio for the second arm: 4/5.
Step 8: Compare the two ratios: 2/3 is not equal to 4/5.
Step 9: Conclude that for the Wheatstone bridge to be balanced, the ratios must be equal, which they are not in this case.
