In a circuit with a 15V battery and two resistors in series (R1 = 5Ω, R2 = 10Ω),

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Question: In a circuit with a 15V battery and two resistors in series (R1 = 5Ω, R2 = 10Ω), what is the voltage across R2?

Options:

Correct Answer: 10V

Solution:

Voltage across R2 = (R2 / (R1 + R2)) * V = (10Ω / (5Ω + 10Ω)) * 15V = 10V.

In a circuit with a 15V battery and two resistors in series (R1 = 5Ω, R2 = 10Ω), what is the voltage across R2?

In a circuit with a 15V battery and two resistors in series (R1 = 5Ω, R2 = 10Ω), what is the voltage across R2?

Step 1: Identify the total voltage in the circuit, which is given as 15V from the battery.
Step 2: Identify the values of the resistors: R1 = 5Ω and R2 = 10Ω.
Step 3: Calculate the total resistance in the circuit by adding R1 and R2: Total Resistance = R1 + R2 = 5Ω + 10Ω = 15Ω.
Step 4: Use the formula to find the voltage across R2: Voltage across R2 = (R2 / Total Resistance) * Total Voltage.
Step 5: Substitute the values into the formula: Voltage across R2 = (10Ω / 15Ω) * 15V.
Step 6: Simplify the calculation: Voltage across R2 = (10 / 15) * 15V = 10V.

Voltage Division – The concept of voltage division in series circuits, where the voltage across a resistor is proportional to its resistance relative to the total resistance.