What is the power dissipated in a resistor of 8Ω when a current of 2A flows thro
Practice Questions
Q1
What is the power dissipated in a resistor of 8Ω when a current of 2A flows through it?
4W
8W
16W
32W
Questions & Step-by-Step Solutions
What is the power dissipated in a resistor of 8Ω when a current of 2A flows through it?
Step 1: Identify the values given in the problem. We have a resistor with a resistance of 8 ohms (Ω) and a current of 2 amperes (A) flowing through it.
Step 2: Recall the formula for power (P) dissipated in a resistor, which is P = I^2 * R, where I is the current and R is the resistance.
Step 3: Substitute the values into the formula. Here, I = 2A and R = 8Ω.
Step 4: Calculate I^2. This means multiplying the current by itself: (2A) * (2A) = 4A^2.
Step 5: Now multiply the result from Step 4 by the resistance: 4A^2 * 8Ω.
Step 6: Perform the multiplication: 4 * 8 = 32.
Step 7: The final result is 32 watts (W), which is the power dissipated in the resistor.
