A circuit contains a 10Ω resistor and a 5Ω resistor in series. What is the total

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Question: A circuit contains a 10Ω resistor and a 5Ω resistor in series. What is the total resistance?

Options:

Correct Answer: 15Ω

Solution:

In series, total resistance R = R1 + R2 = 10Ω + 5Ω = 15Ω.

A circuit contains a 10Ω resistor and a 5Ω resistor in series. What is the total resistance?

A circuit contains a 10Ω resistor and a 5Ω resistor in series. What is the total resistance?

Step 1: Identify the resistors in the circuit. We have a 10Ω resistor and a 5Ω resistor.
Step 2: Understand that when resistors are in series, you add their resistances together.
Step 3: Write down the formula for total resistance in series: R_total = R1 + R2.
Step 4: Substitute the values of the resistors into the formula: R_total = 10Ω + 5Ω.
Step 5: Perform the addition: 10Ω + 5Ω = 15Ω.
Step 6: Conclude that the total resistance of the circuit is 15Ω.

Series Resistance Calculation – In a series circuit, the total resistance is the sum of the individual resistances.