In a bag containing 3 red, 2 blue, and 5 green balls, what is the probability of drawing a blue ball?
Practice Questions
1 question
Q1
In a bag containing 3 red, 2 blue, and 5 green balls, what is the probability of drawing a blue ball?
1/5
1/4
1/10
1/2
Total balls = 3 + 2 + 5 = 10. Probability of drawing a blue ball = Number of blue balls / Total balls = 2/10 = 1/5.
Questions & Step-by-step Solutions
1 item
Q
Q: In a bag containing 3 red, 2 blue, and 5 green balls, what is the probability of drawing a blue ball?
Solution: Total balls = 3 + 2 + 5 = 10. Probability of drawing a blue ball = Number of blue balls / Total balls = 2/10 = 1/5.
Steps: 7
Step 1: Count the number of red balls in the bag. There are 3 red balls.
Step 2: Count the number of blue balls in the bag. There are 2 blue balls.
Step 3: Count the number of green balls in the bag. There are 5 green balls.
Step 4: Add the number of all the balls together: 3 red + 2 blue + 5 green = 10 total balls.
Step 5: Identify how many blue balls there are. There are 2 blue balls.
Step 6: Calculate the probability of drawing a blue ball by dividing the number of blue balls by the total number of balls: 2 blue balls / 10 total balls.
Step 7: Simplify the fraction: 2/10 can be simplified to 1/5.
