A jar contains 4 red, 5 green, and 6 blue marbles. If one marble is drawn at ran

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Question: A jar contains 4 red, 5 green, and 6 blue marbles. If one marble is drawn at random, what is the probability that it is not green?

Options:

Correct Answer: 2/3

Solution:

Total marbles = 4 + 5 + 6 = 15. Non-green marbles = 4 + 6 = 10. Probability = 10/15 = 2/3.

A jar contains 4 red, 5 green, and 6 blue marbles. If one marble is drawn at random, what is the probability that it is not green?

A jar contains 4 red, 5 green, and 6 blue marbles. If one marble is drawn at random, what is the probability that it is not green?

Step 1: Count the total number of marbles in the jar. There are 4 red, 5 green, and 6 blue marbles.
Step 2: Add the number of red, green, and blue marbles together: 4 + 5 + 6 = 15. This is the total number of marbles.
Step 3: Identify the number of non-green marbles. Non-green marbles are red and blue. So, add the number of red and blue marbles: 4 (red) + 6 (blue) = 10.
Step 4: To find the probability of drawing a non-green marble, divide the number of non-green marbles by the total number of marbles: 10 (non-green) / 15 (total) = 10/15.
Step 5: Simplify the fraction 10/15. Both numbers can be divided by 5: 10 ÷ 5 = 2 and 15 ÷ 5 = 3. So, 10/15 simplifies to 2/3.

Probability – The likelihood of an event occurring, calculated as the number of favorable outcomes divided by the total number of possible outcomes.
Counting Outcomes – Understanding how to count the total number of items and categorize them into favorable and unfavorable outcomes.