Calculate ∫ from 0 to 1 of (x^2 + 2x + 1) dx.

Practice Questions

Q1
Calculate ∫ from 0 to 1 of (x^2 + 2x + 1) dx.
  1. 1
  2. 2
  3. 3
  4. 4

Questions & Step-by-Step Solutions

Calculate ∫ from 0 to 1 of (x^2 + 2x + 1) dx.
  • Step 1: Identify the function to integrate, which is (x^2 + 2x + 1).
  • Step 2: Find the antiderivative of the function. The antiderivative of x^2 is x^3/3, the antiderivative of 2x is x^2, and the antiderivative of 1 is x.
  • Step 3: Combine the antiderivatives to get the complete antiderivative: (x^3/3 + x^2 + x).
  • Step 4: Evaluate the antiderivative from the lower limit (0) to the upper limit (1).
  • Step 5: Substitute the upper limit (1) into the antiderivative: (1^3/3 + 1^2 + 1) = (1/3 + 1 + 1).
  • Step 6: Calculate the result from the upper limit: 1/3 + 1 + 1 = 1/3 + 3/3 = 4/3.
  • Step 7: Substitute the lower limit (0) into the antiderivative: (0^3/3 + 0^2 + 0) = 0.
  • Step 8: Subtract the result of the lower limit from the result of the upper limit: (4/3 - 0) = 4/3.
  • Definite Integral – The process of calculating the area under a curve defined by a function over a specific interval.
  • Polynomial Integration – Applying the power rule for integration to polynomial functions.
  • Fundamental Theorem of Calculus – Connecting differentiation and integration, allowing evaluation of definite integrals using antiderivatives.
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