The slope of the tangent to the curve y = x^3 - 3x at x = 1 is:

Practice Questions

Q1
The slope of the tangent to the curve y = x^3 - 3x at x = 1 is:
  1. 0
  2. 1
  3. 2
  4. 3

Questions & Step-by-Step Solutions

The slope of the tangent to the curve y = x^3 - 3x at x = 1 is:
  • Step 1: Identify the function given in the question, which is y = x^3 - 3x.
  • Step 2: Find the derivative of the function. The derivative tells us the slope of the tangent line. The derivative of y = x^3 - 3x is f'(x) = 3x^2 - 3.
  • Step 3: Substitute x = 1 into the derivative to find the slope at that point. Calculate f'(1) = 3(1)^2 - 3.
  • Step 4: Simplify the calculation: f'(1) = 3(1) - 3 = 3 - 3 = 0.
  • Step 5: Conclude that the slope of the tangent to the curve at x = 1 is 0.
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