The equation of the tangent line to the curve y = x^2 at the point (2, 4) is:

Practice Questions

Q1
The equation of the tangent line to the curve y = x^2 at the point (2, 4) is:
  1. y = 2x
  2. y = 4x - 4
  3. y = 4x - 8
  4. y = x + 2

Questions & Step-by-Step Solutions

The equation of the tangent line to the curve y = x^2 at the point (2, 4) is:
  • Step 1: Identify the function. The function is y = x^2.
  • Step 2: Find the derivative of the function to get the slope of the tangent line. The derivative f'(x) = 2x.
  • Step 3: Calculate the slope at the point x = 2. Substitute 2 into the derivative: f'(2) = 2 * 2 = 4.
  • Step 4: Use the point-slope form of the equation of a line. The point is (2, 4) and the slope is 4.
  • Step 5: Write the equation using the point-slope form: y - y1 = m(x - x1), where (x1, y1) is (2, 4) and m is 4.
  • Step 6: Substitute the values into the equation: y - 4 = 4(x - 2).
  • Step 7: Simplify the equation. Distribute 4: y - 4 = 4x - 8.
  • Step 8: Add 4 to both sides to isolate y: y = 4x - 8.
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