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If z1 = 1 + i and z2 = 2 - 3i, what is z1 * z2?
If z1 = 1 + i and z2 = 2 - 3i, what is z1 * z2?
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Practice Questions
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Q1
If z1 = 1 + i and z2 = 2 - 3i, what is z1 * z2?
5 - i
8 - i
7 + i
1 + 5i
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z1 * z2 = (1 + i)(2 - 3i) = 2 - 3i + 2i - 3i^2 = 2 - i + 3 = 5 - i.
Questions & Step-by-step Solutions
1 item
Q
Q: If z1 = 1 + i and z2 = 2 - 3i, what is z1 * z2?
Solution:
z1 * z2 = (1 + i)(2 - 3i) = 2 - 3i + 2i - 3i^2 = 2 - i + 3 = 5 - i.
Steps: 8
Show Steps
Step 1: Identify the complex numbers. Here, z1 = 1 + i and z2 = 2 - 3i.
Step 2: Write the multiplication of the two complex numbers: z1 * z2 = (1 + i)(2 - 3i).
Step 3: Use the distributive property (also known as the FOIL method for binomials) to multiply: (1 * 2) + (1 * -3i) + (i * 2) + (i * -3i).
Step 4: Calculate each part: 1 * 2 = 2, 1 * -3i = -3i, i * 2 = 2i, and i * -3i = -3i^2.
Step 5: Remember that i^2 = -1, so -3i^2 becomes -3 * -1 = 3.
Step 6: Combine all the parts together: 2 - 3i + 2i + 3.
Step 7: Combine like terms: (2 + 3) + (-3i + 2i) = 5 - i.
Step 8: The final result is z1 * z2 = 5 - i.
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