If the vapor pressure of pure solvent is 80 mmHg and the mole fraction of the solvent in the solution is 0.75, what is the vapor pressure of the solution?
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Q1
If the vapor pressure of pure solvent is 80 mmHg and the mole fraction of the solvent in the solution is 0.75, what is the vapor pressure of the solution?
Q: If the vapor pressure of pure solvent is 80 mmHg and the mole fraction of the solvent in the solution is 0.75, what is the vapor pressure of the solution?
Step 1: Identify the vapor pressure of the pure solvent, which is given as 80 mmHg.
Step 2: Identify the mole fraction of the solvent in the solution, which is given as 0.75.
Step 3: Use Raoult's Law formula, which states that the vapor pressure of the solution (P_solution) is equal to the mole fraction of the solvent (X_solvent) multiplied by the vapor pressure of the pure solvent (P_solvent).
Step 4: Substitute the values into the formula: P_solution = X_solvent * P_solvent.
Step 5: Calculate the vapor pressure of the solution: P_solution = 0.75 * 80 mmHg.
