If the vapor pressure of pure solvent is 80 mmHg and the mole fraction of the so
Practice Questions
Q1
If the vapor pressure of pure solvent is 80 mmHg and the mole fraction of the solvent in the solution is 0.75, what is the vapor pressure of the solution?
60 mmHg
80 mmHg
75 mmHg
20 mmHg
Questions & Step-by-Step Solutions
If the vapor pressure of pure solvent is 80 mmHg and the mole fraction of the solvent in the solution is 0.75, what is the vapor pressure of the solution?
Step 1: Identify the vapor pressure of the pure solvent, which is given as 80 mmHg.
Step 2: Identify the mole fraction of the solvent in the solution, which is given as 0.75.
Step 3: Use Raoult's Law formula, which states that the vapor pressure of the solution (P_solution) is equal to the mole fraction of the solvent (X_solvent) multiplied by the vapor pressure of the pure solvent (P_solvent).
Step 4: Substitute the values into the formula: P_solution = X_solvent * P_solvent.
Step 5: Calculate the vapor pressure of the solution: P_solution = 0.75 * 80 mmHg.
Step 7: Conclude that the vapor pressure of the solution is 60 mmHg.
Raoult's Law – Raoult's Law states that the vapor pressure of a solvent in a solution is equal to the vapor pressure of the pure solvent multiplied by the mole fraction of the solvent in the solution.
