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If 50 mL of a 2 M HCl solution is diluted to 200 mL, what is the new molarity?
If 50 mL of a 2 M HCl solution is diluted to 200 mL, what is the new molarity?
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Practice Questions
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Q1
If 50 mL of a 2 M HCl solution is diluted to 200 mL, what is the new molarity?
0.25 M
0.5 M
1 M
2 M
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Using the dilution formula M1V1 = M2V2, (2 M)(50 mL) = M2(200 mL) => M2 = 0.5 M.
Questions & Step-by-step Solutions
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Q
Q: If 50 mL of a 2 M HCl solution is diluted to 200 mL, what is the new molarity?
Solution:
Using the dilution formula M1V1 = M2V2, (2 M)(50 mL) = M2(200 mL) => M2 = 0.5 M.
Steps: 7
Show Steps
Step 1: Identify the initial molarity (M1) and volume (V1) of the HCl solution. Here, M1 = 2 M and V1 = 50 mL.
Step 2: Identify the final volume (V2) after dilution. Here, V2 = 200 mL.
Step 3: Use the dilution formula, which is M1 * V1 = M2 * V2, where M2 is the new molarity we want to find.
Step 4: Plug in the values into the formula: (2 M) * (50 mL) = M2 * (200 mL).
Step 5: Calculate the left side: 2 * 50 = 100. So, we have 100 = M2 * 200.
Step 6: To find M2, divide both sides by 200: M2 = 100 / 200.
Step 7: Calculate the result: M2 = 0.5 M.
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